Physiker haben im Labor die „negative Zeit“ gemessen
https://theconversation.com/physicists-have-measured-negative-time-in-the-lab-278996
Physiker haben im Labor die „negative Zeit“ gemessen
https://theconversation.com/physicists-have-measured-negative-time-in-the-lab-278996
17 Kommentare
Can someone explain to me what this means? Sounds fascinating, but Im just your average idiot.
> We can imagine that his wife, Penelope, would have asked him about that particular time. Odysseus might have replied, “It was nothing. In fact, it was less than nothing. Negative five years I dwelt with Calypso. How else could I have arrived home after only ten years? If you don’t believe me, ask her.”
Did the author **make up** a mythological reference to use? Doesn’t that kind of defeat the whole purpose of referencing something this way?
So what does this all mean? Is a time machine just around the corner?
Sadly, no. Our experiment is fully explained by standard physics.
Homie, time *is particle interactions.* That’s what duration emerges from… Interactions „take time.“ They do not occur instantly. This delay propagates through out the universe and is what we call „time.“ There’s no such thing as negative time. The interactions „take time.“ The system of synchronization that humans use to get to work „on time“ is not „quantum time.“
In the Deveron System??
So I’m also just a layperson, but
> Specifically, we fired a weak laser beam – unrelated to the single photon pulse – through the cloud of atoms, and measured small changes in the phase of the beam’s light to probe whether the atoms were excited.
This sounds to me like the _duration_ of the phase shift is what indicates the excitation duration? For which it would not make sense to be able to measure a negative value. [The abstract](https://journals.aps.org/prl/abstract/10.1103/gjfq-k9dv) shed some light here, I think:
> The time integral of this observed phase shift, properly normalized and averaged over many runs in which the photon is detected after transmission, is the excitation time of interest, in a weak-valued sense.
iiuc, that means: to get a negative value, the integral needs to be negative, so there needs to be an opposite phase shift, correct? In other words, the atoms spend some time in a „less than excited“ state, i.e. a photon of the excitation energy was emitted before the excitation happened.
Does that sound right?
#doubt….. Interpretation is an interesting thing.
another long day at the long day factory, huh
TLDR: scientists fire a photon beam through a cloud of rubidium. Photons hits the cloud, transfer energy to the cloud from one end. Almost immediately the cloud releases a photon from the other end. It seems to happens almost instant, faster than light itself, therefore the ’negative time‘. Keep in mind it’s the writer, not the scientists, highlighting the phrase ’negative time‘. Scientists are not sure, still looking into it.
And without resublimated thiotimoline.
Someone explain this to me in the simplest way possible cause reading through this thread and the article itself I still can’t comprehend what it means at all.
I mean did they really tho?
What a fun and lively read – thank you
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if yoy could show genuine negative Time for a Baryon, and not just a Photon, that would suggest the possibility of Faster-Than-Light travel in Space.
This eperimental observation, to me, isn’t what the article is claiming anyway. The Photon entering and the photon leaving are not the same photon – the Photon gets turned into Electron excitation to a new energy level and then a new Photon is emitted when the Electron drops back to it’s previous level.
There’s no explaination in the article about how the second Photon is emitted before the first Photon is absorbed though…
Until Nomai are arriving on Brittle Hollow before departing from White Hole Station, I won’t believe any „negative time“ nonsense.
Doesn’t negative time also imply negative mass? Or a negative dimension of space-time?