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Time_Reception1482 on 16.04.2026 7:28 a.m. sinx=-3cosx sin^2 x + cos^2 x=10cos^2 x=1 cosx=-1/sqrt(10) sinx=3/sqrt(10) Ez
wjdalswl on 16.04.2026 8:55 a.m. Questions based on trig identities are not usually supposed to require a calculator anyway
Bounded_sequencE on 16.04.2026 9:05 a.m. For convenience, let „(c;s) := (cos(𝜃); sin(𝜃))“. Rewrite the equation as „s = -3c“ and square: s^2 = 9c^2 = 9(1 – s^2) => s^2 = 9/10 => |s| = 3√10 / 10 Solve the given equation for „c = -s/3“, to note only the positive solution is valid: 0 < cos(𝜋-𝜃) = -cos(-𝜃) = -c = s/3 => s = 3√10 / 10
dreamcast98 on 16.04.2026 9:12 a.m. Calculate the tangent value and find the valid theta range(2nd quadrant). Pretty easy I think.
6 Kommentare
sinx=-3cosx
sin^2 x + cos^2 x=10cos^2 x=1
cosx=-1/sqrt(10)
sinx=3/sqrt(10)
Ez
easy
3점이면 솔직히 1분컷 내야죠.
Questions based on trig identities are not usually supposed to require a calculator anyway
For convenience, let „(c;s) := (cos(𝜃); sin(𝜃))“. Rewrite the equation as „s = -3c“ and square:
s^2 = 9c^2 = 9(1 – s^2) => s^2 = 9/10 => |s| = 3√10 / 10
Solve the given equation for „c = -s/3“, to note only the positive solution is valid:
0 < cos(𝜋-𝜃) = -cos(-𝜃) = -c = s/3 => s = 3√10 / 10
Calculate the tangent value and find the valid theta range(2nd quadrant). Pretty easy I think.